((x^2+x)/2)=21

Solution for ((x^2+x)/2)=21 equation:

((x^2+x)/2)=21

We move all terms to the left:

((x^2+x)/2)-(21)=0

We multiply all the terms by the denominator


((x^2+x)-21*2)=0


We calculate terms in parentheses: +((x^2+x)-21*2), so:

(x^2+x)-21*2

We add all the numbers together, and all the variables

(x^2+x)-42

We get rid of parentheses

x^2+x-42

Back to the equation:

+(x^2+x-42)


We get rid of parentheses

x^2+x-42=0

a = 1; b = 1; c = -42;
Δ = b2-4ac
Δ = 12-4·1·(-42)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-13}{2*1}=\frac{-14}{2}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+13}{2*1}=\frac{12}{2}
=6
$